How to make bootable pendrive using diskpart. Command Line Interface

-
you don't have to move mountain here, just follow these simple steps..and let me know in the comments if there is any problem...

Step 1: open "cmd" as administrator .
Step 2: type "diskpart".
Step 3: now type "list disk ".
Step 3: "select disk 1" 
choose your pendrive from the listed disks(note the disk number).
Step 4: now type "clean".
Step 5: "creat partition primary" 
this will mark the pendrive as primary partition memory..which will be detected by the bootloader during the booting process..
Step 6: "select partition 1"
Step 7: "active"
Step 8: "format fs=ntfs quick"
Step 9:"assign"
Step 10: "exit"
Step 11: now copy the windows distribution files to the pendrive directly.

Note: All the texts in the double quotes are the command and you must perform it in the sequence.

Comments

Post a Comment

Popular posts from this blog

Contest Leaderboard: hackerrank problem (Level medium)

-
Problem Statement: You did such a great job helping Julia with her last coding contest challenge that she wants you to work on this one, too! The total score of a hacker is the sum of their maximum scores for all of the challenges. Write a query to print the hacker_id , name , and total score of the hackers ordered by the descending score. If more than one hacker achieved the same total score, then sort the result by ascending hacker_id . Exclude all hackers with a total score of from your result. Tables: Hackers: The hacker_id is the id of the hacker, and name is the name of the hacker.  Submissions: The submission_id is the id of the submission, hacker_id is the id of the hacker who made the submission, challenge_id is the id of the challenge for which the submission belongs to, and score is the score of the submission.   Solutions: select h.hacker_id,h.name,sum(sscore) from Hackers h inner join (select s.hacker_id,max(score) as sscore from Submissions s g
Read more

Placements: SQL Advance join (Hackerrank Problem)

-
Image
Problem: You are given three tables:  Students , Friends and Packages.   Students contains two columns: ID  and Name . Friends contains two columns: ID and Friend_ID ( ID of the ONLY best friend). Packages  contains two columns: ID and Salary (offered salary in $ thousands per month). Write a query to output the names of those students whose best friends got offered a higher salary than them. Names must be ordered by the salary amount offered to the best friends. It is guaranteed that no two students got same salary offer. Solution: select temp1.sn from (select S.ID si,S.Name sn,P.Salary ps from Students S join Packages P on S.ID=P.ID) temp1 join (select FF.ID fi,FF.Friend_ID fd,PP.Salary pps from Friends FF join Packages PP on FF.Friend_ID=pp.ID) temp2 on temp1.si=temp2.fi and temp1.ps<temp2.pps order by temp2.pps asc ; Explanation: As the problem states that we have to select the name of the friend whose salary is lesser than what his/her friend is ha
Read more

The Occupation: hackerrank problem

-
Problem Statement: Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation . The output column headers should be Doctor , Professor , Singer , and Actor , respectively. Note: Print NULL when there are no more names corresponding to an occupation. Table:   'OCCUPATIONS' table contain the column 'Name' and 'Occupation' Solution: select doc,prof,singer,act from ( select row_number() over(partition by Occupation order by Name) ron,Name as n,Occupation as o from OCCUPATIONS ) pro pivot (max(n)  for o in ('Doctor' as doc,'Actor' as act,'Professor' as prof,'Singer' as singer))  order by ron asc; Explanation: in the above query statement i am using row_number() function with the 'partition by' clause to append one column that contains row_number for each row in the subquery. in the subquery while assigning row_number() we
Read more